@ARPIT: I published your comment because I assumed...
Steve · 2012-12-18T09:24:23.395000
@ARPIT: I published your comment because I assumed you wanted to test whether it gave you the formula you expected. Looking at the comment window I imagine you must have been disappointed (for other readers, the source code only shows up, because Mathjax isn't loaded in the comment window).
However, as you can see looking at the comments as a part of the blog, it renders beautifully - well done!
hi i have a hard questin please help,q:You are pla...
james · 2012-12-21T21:03:43.003000
hi i have a hard questin please help,q:You are playing a dice game with your friend by rolling two standard dice and recording the sum of two numbers. You will win when two consecutive outcomes are 7. Your friend will win when three consecutive outcomes are in increasing order. You will continue rolling until one of you will win. What is the probability that you will win?
Examples:If the outcomes are 10,4,6,6,7,7 you will win. If the outcomes are 7,3,7,9 your friend will win.
Anonymous · 2012-12-21T21:06:27.145000
This comment has been removed by a blog administrator.
\[P(E) = {n \choose k} p^k (1-p)^{n-k}\]
Anonymous · 2013-05-15T22:51:51.757000
\[P(E) = {n \choose k} p^k (1-p)^{n-k}\]
As a matter of curiosity, I'm using MathJax wi...
Gavin (GRP): Thanks for your note. This isn't ...
Steve · 2013-11-24T08:59:38.055000
Gavin (GRP): Thanks for your note. This isn't a competition, so I am always happy to hear about other ways people can achieve the ends they want. If anyone else has tips feel free to drop them here.
I'll be writing about the IPython Notebook soon, which allows you to blog not only Mathjax-based mathematics but also code in various different programming languages. The really good news is that you can, if the author makes it available, actually run the executable version of the same notebooks on your own machine, tweaking the code for your own purposes.
MathJax seems to be the most powerful way to put m...
Matthew Martin · 2013-12-14T01:11:32.500000
MathJax seems to be the most powerful way to put math on the web, but there are many limitations. For one thing, MathJax is incredibly slow. In general, javascript shouldn't be used for the appearance layer of a webpage because it is slow, single-thread, and degrades extremely ungracefully compared to HTML and CSS. But even among javascript-based rendering engines for math on the web, MathJax is roughly 5 times slower than alternatives like jqMath, though it is admittedly much more versatile.
Additionally, I want to point out that if you embed this code in a particular blog post, it will still apply to all the code that appears on the page, including other blog posts that you may not have wanted to put math in. For that reason, I recommend changing the code to use a more unique identifier than the dollar sign, so that you can freely use dollar signs in other posts.
\[P(E) = {n \choose k} p^k (1-p)^{n-k}\]
ARPIT · 2012-12-18T09:18:55.964000
\[P(E) = {n \choose k} p^k (1-p)^{n-k}\]
@ARPIT: I published your comment because I assumed...
Steve · 2012-12-18T09:24:23.395000
@ARPIT: I published your comment because I assumed you wanted to test whether it gave you the formula you expected. Looking at the comment window I imagine you must have been disappointed (for other readers, the source code only shows up, because Mathjax isn't loaded in the comment window).However, as you can see looking at the comments as a part of the blog, it renders beautifully - well done!
hi i have a hard questin please help,q:You are pla...
james · 2012-12-21T21:03:43.003000
hi i have a hard questin please help,q:You are playing a dice game with your friend by rolling two standard dice and recording the sum of two numbers. You will win when two consecutive outcomes are 7. Your friend will win when three consecutive outcomes are in increasing order. You will continue rolling until one of you will win. What is the probability that you will win?Examples:If the outcomes are 10,4,6,6,7,7 you will win. If the outcomes are 7,3,7,9 your friend will win.
Anonymous · 2012-12-21T21:06:27.145000
This comment has been removed by a blog administrator.\[P(E) = {n \choose k} p^k (1-p)^{n-k}\]
Anonymous · 2013-05-15T22:51:51.757000
\[P(E) = {n \choose k} p^k (1-p)^{n-k}\]As a matter of curiosity, I'm using MathJax wi...
GRP · 2013-11-24T08:01:04.384000
As a matter of curiosity, I'm using MathJax with a 'Classic' Blogger template.Gavin (GRP): Thanks for your note. This isn't ...
Steve · 2013-11-24T08:59:38.055000
Gavin (GRP): Thanks for your note. This isn't a competition, so I am always happy to hear about other ways people can achieve the ends they want. If anyone else has tips feel free to drop them here.I'll be writing about the IPython Notebook soon, which allows you to blog not only Mathjax-based mathematics but also code in various different programming languages. The really good news is that you can, if the author makes it available, actually run the executable version of the same notebooks on your own machine, tweaking the code for your own purposes.
MathJax seems to be the most powerful way to put m...
Matthew Martin · 2013-12-14T01:11:32.500000
MathJax seems to be the most powerful way to put math on the web, but there are many limitations. For one thing, MathJax is incredibly slow. In general, javascript shouldn't be used for the appearance layer of a webpage because it is slow, single-thread, and degrades extremely ungracefully compared to HTML and CSS. But even among javascript-based rendering engines for math on the web, MathJax is roughly 5 times slower than alternatives like jqMath, though it is admittedly much more versatile.Additionally, I want to point out that if you embed this code in a particular blog post, it will still apply to all the code that appears on the page, including other blog posts that you may not have wanted to put math in. For that reason, I recommend changing the code to use a more unique identifier than the dollar sign, so that you can freely use dollar signs in other posts.
\begin{align} \sin^{2}\alpha+\cos^{2}\alpha=1 \end...
Anonymous · 2014-03-20T18:45:59.078000
\begin{align}\sin^{2}\alpha+\cos^{2}\alpha=1
\end{align}
\[P(E) = {n \choose k} p^k (1-p)^{n-k}\]
Anonymous · 2014-05-12T23:29:41.487000
\[P(E) = {n \choose k} p^k (1-p)^{n-k}\]Older comments · Page 2 of 3 · Newer comments
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